Given: A=I2−2MMT
⇒A2=(I2−2MMT)(I2−2MMT)
⇒A2=I2−2MMT−2MMT+4MMTMMT
⇒A2=I2−4MMT+4MMT asMTM=I1
⇒A2=I2
Also, AX=λX
⇒A2X=λAX
⇒X=λ(λX) {\text{as}{A}^{2}={I}_{2}&AX=\lambda X}
⇒X=λ2X
⇒X(λ2−1)=0
⇒λ2=1
⇒λ=±1
So, sum of square of all possible values =2
JEE Main 2024 — Mathematics Algebra
Let A=I2−2MMT, where M is real matrix of order 2×1 such that the relation MTM=I1 holds. If λ is a real number such that the relation AX=λX holds for some non-zero real matrix X of order 2×1, then the sum of squares of all possible values of λ is equal to:
Held on 1 Feb 2024 · Verified 6 Jul 2026.
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