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Let the relations R_1 and R_2 on the set X=1,2,3, …, 20 be given by R_1=(x, y): 2 x-3 y=2 and R_2=(x, y):-5 x+4 y=0. If M and N be the minimum number…

JEE Main 2024 — Mathematics Algebra

2024mcqmedium

Let the relations R1R_1R1​ and R2R_2R2​ on the set X={1,2,3,…,20}X=\{1,2,3, \ldots, 20\}X={1,2,3,…,20} be given by R1={(x,y):2x−3y=2}R_1=\{(x, y): 2 x-3 y=2\}R1​={(x,y):2x−3y=2} and R2={(x,y):−5x+4y=0}R_2=\{(x, y):-5 x+4 y=0\}R2​={(x,y):−5x+4y=0}. If MMM and NNN be the minimum number of elements required to be added in R1R_1R1​ and R2R_2R2​, respectively, in order to make the relations symmetric, then M+NM+NM+N equals

Official previous-year question

Held on 6 Apr 2024 · Verified 6 Jul 2026.

Options

  1. A

    12

  2. B

    16

  3. C

    8

  4. D

    10

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