n(3)⇒ multiple of 3102,105,108,…..,699 Tn=699=102+(n−1)(3)n=200n(3)=200∵n(4)⇒ multiple of 4 100,104,108,….,700Tn=700=100+(n−1)(4)n=151n(4)=151n(3∩4)⇒ multiple of 3&4 both 108,120,132,….,696Tn=696=108+(n−1)(12)n=50n(3∩4)=50n(3∪4)=n(3)+n(4)−n(3∩4)=200+151−50=301n(3∪4)= Total −n(3∪4)= neither a multiple of 3 nor a multiple of 4=601−301=300