nCrn+1Cr=3555(r+1)!(n−r)(n+1)!!n!r!(n−r)!=711r+1(n+1)=711 7n=4+11rn−1Cr−1nCr=2135r!(n−r)!n!=(n−1)!(r−1)!(n−r)!=35rn=353n=5r By solving r=6n=102n+5r=50
Let 0 ≤ ≤ n. If ^ n+1 C_ +1: ^n C_ : ^ n-1 C_ -1=55: 35: 21, then 2 n+5 is equal to:
JEE Main 2024 — Mathematics Algebra
Let 0≤r≤n. If n+1Cr+1:nCr:n−1Cr−1=55:35:21, then 2n+5r is equal to:
Held on 6 Apr 2024 · Verified 6 Jul 2026.
Options
- A
50
- B
62
- C
55
- D
60
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