N=2310=231×10 =3×11×7×2×5 A={2,3,5,7,11} f(x)=[log2(x2+[5x3])]f(2)=[log2(5)]=2f(3)=[log2(14)]=3f(5)=[log2(25+25)]=5f(7)=[log2(117)]=6f(11)=[log2387]=8 Range of f:B={2,3,5,6,8} No. of one-one functions =5!=120
JEE Main 2024 — Mathematics Algebra
Let [t] be the greatest integer less than or equal to t. Let A be the set of all prime factors of 2310 and f:A→Z be the function f(x)=[log2(x2+[5x3])]. The number of one-to-one functions from A to the range of f is
Held on 8 Apr 2024 · Verified 6 Jul 2026.
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120
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