Let AA111=a1b1c1a2b2c2a3b3c3=3111 ⇒a1+a2+a3=3 ...(1) ⇒b1+b2+b3=3 ...(2) ⇒c1+ca2+c3=3 ...(3) Now, $\begin{aligned}
& |A|=\left(a_1 b_2 c_3+a_2 b_3 c_1+a_3 b_1 c_2\right) \
& -\left(a_3 b_2 c_1+a_2 b_1 c_3+a_1 b_3 c_2\right)
\end{aligned}\thereforeFromaboveinformation,clearly|\mathrm{A}|_{\max }=27,whena_1=3, b_2=3, c_3=3$