Given: α=(4!)3!(4!)!,β=(5!)4!(5!)!
⇒α=(4!)6(24)!,β=(5!)24(120)!
If 24 distinct objects are divided into 6 groups of 4 objects in each group, then the number of ways of formation of group is=(4!)6.6!24!∈N
Similarly, let 120 distinct objects are divided into 24 groups of 5 objects in each group.
So, the number of ways of formation of groups
=(5!)24⋅24!(120)!∈N