Let, y=∣P−1AP−2I∣
⇒y=∣P−1AP−2P−1P∣
⇒y=∣(P−1I)(A−2I)P∣
⇒y=∣P−1I∣∣A−2I∣∣P∣
We know that, ∣A∣=∣A−1∣1.
⇒y=∣A−2I∣
⇒y=∣2631232112∣−∣200020002∣
⇒y=∣0631032110∣
⇒y=0−(0−33)+2(18−0)
⇒y=69
Now, prime factor of 69 is 3 and 23.
So, sum =26
JEE Main 2024 — Mathematics Algebra
Let A=[2631232112] and P=[157201025]. The sum of the prime factors of ∣P−1AP−2I∣ is equal to
Held on 29 Jan 2024 · Verified 6 Jul 2026.
26
27
66
23
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