Δ=175491−1μ2=0⇒(18−μ)−4(14−5μ)−(7−45)=0⇒μ=0Δ=Δx=Δy=Δz=0 (For infinite solution) Δx=λ−3−1491−1μ2=0λ(18−μ)−4(−6+μ)−1(−3+9)=018λ+24−6=0⇒λ=−1
If the system of equations x+4 y-z=λ, 7 x+9 y+μ z=-3,5 x+y+2 z=-1 has infinitely many solutions, then (2 μ+3 λ) is equal to :
JEE Main 2024 — Mathematics Algebra
If the system of equations x+4y−z=λ,7x+9y+μz=−3,5x+y+2z=−1 has infinitely many solutions, then (2μ+3λ) is equal to :
Held on 8 Apr 2024 · Verified 6 Jul 2026.
Options
- A
3
- B
-3
- C
-2
- D
2
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