Coeff. of x4=nC4 Coeff. of x5=nC5 Coeff. of x6=nC6nC4,nC5,nC6….AP2C5=nC4+nC62=nC5nC4+nC5nC6{nCrnCr=rn−r+1}2=n−45+6n−512(n−4)=30+n2−9n+20n2−21n+98=0(n−14)(n−7)=0nmax=14nmin=7
If the coefficients of x^4, x^5 and x^6 in the expansion of (1+x)^n are in the arithmetic progression, then the maximum value of n is:
JEE Main 2024 — Mathematics Algebra
If the coefficients of x4,x5 and x6 in the expansion of (1+x)n are in the arithmetic progression, then the maximum value of n is:
Held on 4 Apr 2024 · Verified 6 Jul 2026.
Options
- A
7
- B
21
- C
28
- D
14
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