Given: ∣z+23+4i∣;∣z∣≤1
Let, z=x+iy
And ∣z∣=1 gives x2+y2=1, which represents a circle having centre at (0,0) and radius as 1 unit.
Now, ∣z+23+4i∣ gives the distance of z from (−23,−2)

So, we need to find the minimum distance of AP.
⇒AP=OP−OA
⇒AP=(−23−0)2+(0+2)2−1
⇒AP=49+4−1
⇒AP=25−1
⇒AP=23