k=4(4x+4x1)+(42x+42x1)≥2≥2 k≥10
For x geqslant 0, the least value of K, for which 4^1+x+4^1-x, K 2, 16^x+16^-x are three consecutive terms of an A.P., is equal to :
JEE Main 2024 — Mathematics Algebra
For x⩾0, the least value of K, for which 41+x+41−x,2K,16x+16−x are three consecutive terms of an A.P., is equal to :
Held on 5 Apr 2024 · Verified 6 Jul 2026.
Options
- A
8
- B
4
- C
10
- D
16
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