Let f(x)=2x2−8x+k=0

f(1)>0
f(2)<0
f(3)>0
Now, f(1)>0⇒2−8+k>0⇒k>6......(1)
f(2)<0⇒8−16+k<0⇒k<8......(2)
f(3)>0⇒18−24+k>0⇒k>6......(3)
From equations (1),(2)&(3),
k∈(6,8)
∴ Integral value of k=7
Therefore number of integral value of k is one
The number of integral values of k, for which one root of the equation 2x2−8x+k=0 lies in the interval (1,2) and its other root lies in the interval (2,3), is :
Held on 1 Feb 2023 · Verified 6 Jul 2026.
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