We know that,
Maximum value of n for pn where p is prime divides the number a! is given by,
[pa]+[p2a]+[p3a]+[p4a]+...
Since, 3 is a prime number, so we have
=[366]+[3266]+[3366]+[3466]+...
=22+7+2+0
=31
So, maximum value of n is 31.
JEE Main 2023 — Mathematics Algebra
The largest natural number n such that 3n divides 66! is _______
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