Given,
Function f(x)=e2logex−(2x+3)log(x+1)(x−2),x∈R
To find domain we will take following cases:
Case-1:
x−2>0⇒x>2
x∈(2,∞)
Case-2:
x+1>0⇒x>−1
And, x+1=1⇒x=0
x∈(−1,0)∪(0,∞)
Case-3:
x>0
x∈(0,∞)
Case-4:
e2loge(x)−(2x+3)⇒x2−2x−3=0
⇒(x−3)(x+1)=0
x=−1,3
From case (1)∩case (2)∩case (3)∩case (4) we get,
x∈(2,∞)−3