The given expansion is (2x2+2x1)11.
The general term in the binomial expansion of (x+a)n is given by Tr+1=Crnxn−rar.
⇒Tr+1=Cr11(2x2)11−r(2x1)r
=Cr11(211−r−r)x22−2r−r
Now for coefficient of x7⇒22−3r=7
⇒r=5
Coefficient of x7 is C511(211−5×2)
Now for coefficient of x10⇒22−3r=10
⇒r=4
Coefficient of x10 is C411(211−2×4)
We need the absolute difference, we get it by ∣C511(211−5×2)−C411(211−4×2)∣.
=∣924−2640∣=1716
=123−12
Hence the absolute difference is =123−12.