We have been given that
∣A∣=m−n, where 4m+n=22.......(i)
and 17m+4n=93.......(ii)
Solving (i) and (ii)
m=5,n=2
Order =5
⇒∣A∣=3
We know that ∣adjA∣=∣A∣w−1∣adj(adjA)∣=∣A∣(w−1)2 where w×w is the order of the matrix.
∴det(nadj(adj(mA)))
=∣2adj(adj(5A))∣
=25∣5A∣16
=25580∣A∣16=25⋅316⋅580
=31158065
So, a+b+c=96
Hence this is the required option.