The given expansion is (3x2−2x51)7.
The general term in the binomial expansion of (x+a)n is given by Tr+1=Crnxn−rar.
⇒Tr+1=Cr7(3x2)7−r(2x5−1)r
=Cr7(−1)r(2r37−r)x14−2r−5r
Now for term independent of x⇒14−2r−5r=0
⇒r=2
Coefficient of x0 is C27(−1)2×(2237−2)
=27×6×2235.
⇒α=45103
⇒[α]=1275
Hence this is the required answer.