Given,
System of equations,
6λx−3y+3z=4λ2
2x+6λy+4z=1
3x+2y+3λz=λ
For no solution △=0,
So, ∣6λ23−36λ2343λ∣=0
⇒9λ3−7λ−2=0
⇒(λ−1)(3λ+1)(3λ+2)=0
Hence, λ∈1,3−1,3−2
Now putting the value of λ in 12λ∈S∑∣λ∣ we get,
12λ∈S∑∣λ∣=12×(1+31+32)=24
JEE Main 2023 — Mathematics Algebra
Let S be the set of values of λ, for which the system of equations
6λx−3y+3z=4λ2, 2x+6λy+4z=1 and 3x+2y+3λz=λ has no solution. Then,12λ∈S∑∣λ∣ is equal to _______.
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