Let the common difference of an A.P. be d, then
a1+a2+a3+a4=50
⇒4a+6d=50
⇒32+6d=50
⇒d=3
Also,
an−3+an−2+an−1+an=170
⇒4a+(4n−10)⋅d=170
⇒32+(4n−10)⋅3=170
⇒n=14
So, middle terms are
a7=a+6d=26,a8=a+7d=29
⇒a7⋅a8=754
JEE Main 2023 — Mathematics Algebra
Let a1=8,a2,a3,….an be an A.P. If the sum of its first four terms is 50 and the sum of its last four terms is 170 , then the product of its middle two terms is _____ .
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