Given equation is
∣adj(adj(adj.A))∣=124
⇒∣A∣(n−1)3=124
∵n=3
⇒∣A∣(3−1)3=124
⇒∣A∣8=124
⇒∣A∣2=12
⇒∣A∣=23
Now, ∣A−1adjA∣=∣A−1∣.∣adjA∣=∣A∣1×∣A∣3−1
=∣A∣=23
Let A be a 3×3 matrix such that ∣adj(adj(adj.A))∣=124. Then ∣A−1adjA∣ is equal to
Held on 24 Jan 2023 · Verified 6 Jul 2026.
23
6
12
1
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