Given,
a1,a2,a3,…. be a GP of increasing positive numbers,
And the product of fourth and sixth terms is 9
So, a4⋅a6=9⇒(a5)2=9⇒a5=3
Also given the sum of fifth and seventh terms is 24,
So, a5+a7=24
⇒a5+a5r2=24
⇒(1+r2)=8⇒r=7
Now using a5=3⇒a1r4=3⇒a1=r43=493
Then, a1a9+a2a4a9+a5+a7
=493×493×(7)8+493×7×493×(7)3×493×(7)8+493×(7)4+493×(7)6
=9+27+3+21=60