f(x) is given as
f(x)=2xn+λ,λ∈R,n∈N
∵f(4)=133
⇒133=2×4n+λ...(1)
∵f(5)=255
⇒255=2×5n+λ...(2)
Now, (2)−(1)
122=2(5n−4n)
⇒5n−4n=61
\therefore n=3&\lambda =5
Now f(3)−f(2)=2(33−23)=38
Number of divisors =1,2,19,38 and their sum is 60
JEE Main 2023 — Mathematics Algebra
Let f(x)=2xn+λ,λ∈R,n∈N, and f(4)=133, f(5)=255. Then the sum of all the positive integer divisors of (f(3)−f(2)) is
Held on 25 Jan 2023 · Verified 6 Jul 2026.
61
60
58
59
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