Given,
z1=2+3i and z2=3+4i and the set
S=z∈C:∣z−z1∣2−∣z−z2∣2=∣z1−z2∣2,
Now putting the value of z=x+iy,z1=2+3i and z2=3+4i in ∣z−z1∣2−∣z−z2∣2=∣z1−z2∣2 we get,
⇒((x−2)2+(y−3)2)−((x−3)2−(y−4)2)=1+1
⇒x+y=7
Which is a straight line with intercept 7 on x&y axis, so sum of intercept will be 7+7=14.