General term in the binomial expansion of (x32+x3α)22 is
Tr+1=Cr22(x32)22−r(x3α)r
⇒Tr+1=Cr22(x)344−11rαr
For term independent of x,
344−11r=0
⇒r=4
So,
T5=C422α4=7315
⇒(4!×18!22!)α4=7315
⇒7315α4=7315
⇒α4=1
⇒∣α∣=1
JEE Main 2023 — Mathematics Algebra
If the term without x in the expansion of (x32+x3α)22 is 7315, then ∣α∣ is equal to _____ .
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