Given:
f(x)=1+x2[x]
So,
f(x)=1+x22;f(x)=1+x23;f(x)=1+x24;f(x)=1+x25;x∈[2,3)x∈[3,4)x∈[4,5)x∈[5,6)

Hence,
f(x)∈(375,52]
If the domain of the function f(x)=1+x2[x], where [x] is greatest integer ≤x, is [2,6), then its range is
Held on 31 Jan 2023 · Verified 6 Jul 2026.
(265,52]−299,10927,8918,539
(265,52]
(375,52]−299,10927,8918,539
(375,52]
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