Given that 1542022
We know that (a+x)n=C0nanx0+C1nan−1x1+.....+Cnna0xn
⇒1542022=15161011=15(15+1)1011
=15C01011(15)1011+C11011(15)1010+.....+C10111011(15)0
=15C01011(15)1011+C11011(15)1010+.....+C10101011(15)1+151
∴ Fractional part of1542022=151
Hence this is the required option.