We have been given that
f(g(x))=x+3−x
⇒f(x+1)=x+3−x
Put x+1=t
x=t−1
x=(t−1)2
⇒f(t)=(t−1)2+3−(t−1)
⇒f(0)=1+3+1=5
Hence this is the correct option.
JEE Main 2023 — Mathematics Algebra
For x∈R, two real valued functions f(x) and g(x) are such that, g(x)=x+1 and fog(x)=x+3−x. Then f(0) is equal to
Held on 13 Apr 2023 · Verified 6 Jul 2026.
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