Given,
x2+3x+103x2−9x+17=3x2+5x+125x2−7x+19
⇒x2+3x+10x2+3x+10+2x2−12x+7=3x2+5x+123x2+5x+12+2x2−12x+7
⇒1+x2+3x+102x2−12x+7=1+3x2+5x+122x2−12x+7
⇒(2x2−12x+7)(x2+3x+101−3x2+5x+121)=0
2x2−12x+7=0 Or 3x2+5x+12=x2+3x+10
For 2x2−12x+7=0
Sum of roots=212=6
Or 3x2+5x+12=x2+3x+10
⇒2x2+2x+2=0
⇒x2+x+1=0
No real roots as D=1−4<0