We know 2023=7×289
So (2021)2022+(2022)2021
=(2023−2)2022+(2023−1)2021
=7m1+22022+7m2+(−1)2021
=7(m1+m2)+8674−1
=7(m1+m2)+(7+1)674−1
=7(m1+m2)+7m3+1−1
=7(m1+m2+m3)
This is a multiple of 7
Hence, remainder is 0
JEE Main 2022 — Mathematics Algebra
The remainder when (2021)2022+(2022)2021 is divided by 7 is
Held on 27 Jul 2022 · Verified 6 Jul 2026.
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