Given linear equations are
x+y+z=α
αx+2αy+3z=−1
x+3αy+5z=4
For this system of linear equations to have inconsistent solution
D=∣1α112α3α135∣=0
⇒(α−1)2=0
⇒α=1
Now for α=1
D1=∣1−14123135∣
=(10−9)−(−5−12)+(−3−8)
=1+17−11=0
Hence, for α=1 the system of equation has inconsistent solution.