For the system of linear equations
2x−3y+5z=9
x+3y−z=−18
3x−y+(λ2−∣λ∣)z=16 to have no solutions,
Δ should be equal to 0.
i.e. Δ=∣213−33−15−1λ2−∣λ∣∣
=2(3λ2−3∣λ∣−1)+3(λ2−∣λ∣+3)+5(−1−9)
=9λ2−9∣λ∣−43
=9∣λ∣2−9∣λ∣−43
Now Δ=0 for 2 values of ∣λ∣ as for the above quadratic the value of determinant is greater than zero.
So, 2 values of λ satisfy the system of equations to obtain no solution.