Given the ratio of the sum of the first five terms to the sum of the first nine terms is 5:17,
So, S9S5=175⇒29(2a+8d)25(2a+4d)=175
⇒17(2a+4d)=9(2a+8d)
⇒34a+68d=18a+72d
⇒d=4a
Now a15=a+14d=57a
Also given 110<a15<120
⇒110<57a<120
⇒a=2∴d=8
So, S10=210(2×2+9×8)=380