Using A.M≥G.M, we get
5x+x+x+y+y≥5x3⋅(y)2
⇒53x+2y≥5x3y2
⇒53x+2y≥5(215)(∵x3y2=215)
⇒3x+2y≥5⋅(2)15/5
⇒3x+2y⩾5×23
⇒3x+2y⩾40
∴ The minimum value of 3x+2y is 40
JEE Main 2022 — Mathematics Algebra
Let x,y>0. If x3y2=215, then the least value of 3x+2y is
Held on 24 Jun 2022 · Verified 6 Jul 2026.
30
32
36
40
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