Given, f(n)={\begin{matrix}2n, & \mathrm{if}n=1,2,3,4,5 \\ 2n-11 & \mathrm{if}n=6,7,8,9,10\end{matrix}
So, f(1)=2, f(2)=4, .....f(5)=10
And f(6)=1, f(7)=3, f(8)=5 ......f(10)=9
f(g(n))={\begin{matrix}n+1 & ; & n\in \mathrm{odd} \\ n-1 & ; & n\in \mathrm{even}\end{matrix}
So, f(g(10))=9⇒g(10)=10
f(g(1))=2⇒g(1)=1
f(g(2))=1⇒g(2)=6
f(g(3))=4⇒g(3)=2
f(g(4))=3⇒g(4)=7
f(g(5))=6⇒g(5)=3
So, g(10)⋅[g(1)+g(2)+g(3)+g(4)+g(5)]
=10⋅[1+6+2+7+3]=190