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Let n≥ 5 be an integer. If 9^n-8n-1=64α and 6^n-5n-1=25β, then α -β is equal to:

JEE Main 2022 — Mathematics Algebra

2022mcqhard

Let n≥5n\geq 5n≥5 be an integer. If 9n−8n−1=64α{9}^{n}-8n-1=64\alpha9n−8n−1=64α and 6n−5n−1=25β{6}^{n}-5n-1=25\beta6n−5n−1=25β, then α−β\alpha -\betaα−β is equal to:

Official previous-year question

Held on 29 Jun 2022 · Verified 6 Jul 2026.

Options

  1. A

    1+C2n(8−5)+C3n(82−52)+…+Cnn(8n−1−5n−2)1+C2n(8-5)+C3n({8}^{2}-{5}^{2})+\ldots +Cnn({8}^{n-1}-{5}^{n-2})1+C2n(8−5)+C3n(82−52)+…+Cnn(8n−1−5n−2)

  2. B

    1+C3n(8−5)+C4n(82−52)+…+Cnn(8n−2−5n−2)1+C3n(8-5)+C4n({8}^{2}-{5}^{2})+\ldots +Cnn({8}^{n-2}-{5}^{n-2})1+C3n(8−5)+C4n(82−52)+…+Cnn(8n−2−5n−2)

  3. C

    C3n(8−5)+C4n(82−52)+…+Cnn(8n−2−5n−2)C3n(8-5)+C4n({8}^{2}-{5}^{2})+\ldots +Cnn({8}^{n-2}-{5}^{n-2})C3n(8−5)+C4n(82−52)+…+Cnn(8n−2−5n−2)

  4. D

    C4n(8−5)+C5n(82−52)+…+Cnn(8n−3−5n−3)C4n(8-5)+C5n({8}^{2}-{5}^{2})+\ldots +Cnn({8}^{n-3}-{5}^{n-3})C4n(8−5)+C5n(82−52)+…+Cnn(8n−3−5n−3)

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