Given,
k=1∑10k4+k2+1k=nm
⇒21k=1∑10(k2+k+1)(k2−k+1)(k2+k+1)−(k2−k+1)=nm
by using the formula x4+x2+1=(x2+x+1)(x2−x+1)
⇒21(k=1∑10((k2−k+1)1−k2+k+11))=nm
⇒21(1−31+31−71+71−.........−1111)=nm
⇒21(1−1111)=nm
⇒11155=nm
So, m+n=166
JEE Main 2022 — Mathematics Algebra
If k=1∑10k4+k2+1k=nm, where m and n are co-prime, then m+n is equal to
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