Let I=1+(1+C049+C149+…+C4949)(C250+C450+…+C5050)
As C049+C149+…+C4949=249
and C050+C250+…+C5050=249
⇒C250+C450+….+C5050=249−1
∴I=1+(249+1)(249−1)=298
Now comparing I=2nm we get, m=1 and n=98
So, m+n=99
JEE Main 2022 — Mathematics Algebra
If 1+(2+C149+C249+….+C4949)(C250+C450+…..+C5050) is equal to 2n.m, where m is odd, then n+m is equal to _____ .
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