Let the A.P. be a,A1,A2...An,100
Here, common difference, d=n+1100−a
Given AnA1=71⇒100−da+d=71...(i)
Also a+n=33
From options, when n=23, a=10andd=2490=415
from (i) 100−41510+415=38555=71
JEE Main 2022 — Mathematics Algebra
If n arithmetic means are inserted between a and 100 such that the ratio of the first mean to the last mean is 1:7 and a+n=33, then the value of n is
Held on 28 Jun 2022 · Verified 6 Jul 2026.
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