We know that (x,y)∈R,(y,x)∈R⇒symmetric
(x,y)\in R,(y,z)\in R&(z,x)\in R\Rightarrowtransitive
\begin{matrix}0<|x-y|\leq 1 \\ 0<|y-x|\leq 1\end{matrix}}is symmetric
let
0<∣x−y∣≤1 .......(1)
(1,2)∈R and (2,3)∈R satisfy the equation (1)
but (1,3)∈/R not satisfied
Hence 0<∣x−y∣≤1 is symmetric but not transitive relation