x3−2x2+2x−1=0
x=1 satisfying the equation
∴x−1 is factor of x3−2x2+2x−1
=(x−1)(x2−x+1)=0
x=1,21+i3,21−i3
x=1,−ω2,−ω
sum of 162th power of roots
=(1)162+(−ω2)162+(−ω)162
=1+(ω)324+(ω)162
=1+1+1=3
JEE Main 2021 — Mathematics Algebra
The sum of 162th power of the roots of the equation x3−2x2+2x−1=0 is ______.
Held on 26 Feb 2021 · Verified 6 Jul 2026.
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