log4(x−1)=log2(x−3)⇒21log2(x−1)=log2(x−3)
⇒log2(x−1)1/2=log2(x−3)
⇒(x−1)1/2=x−3
⇒x−1=x2+9−6x
⇒x2−7x+10=0
⇒(x−2)(x−5)=0
⇒x=2,5
But x=2 because it is not satisfying the domain of given equation i.e log2(x−3)→ its domain x>3 finally x is 5
∴ No. of solutions =1.