We have, Re(z2)+2(Im(z))2+2Re(z)=0
where z=x+iy
Equation of circle is (x2−y2)+2y2+2x=0
x2+y2+2x=0
Centre: (−1,0)
Parabola : (x−3)2=y−4
Vertex : (3,4)
Equation of line ≡y−0=3+14−0(x+1)
⇒y=x+1
Hence, y− intercept =1.
JEE Main 2021 — Mathematics Algebra
The equation of a circle is Re(z2)+2(Im(z))2+2Re(z)=0, where z=x+iy. A line which passes through the centre of the given circle and the vertex of the parabola, x2−6x−y+13=0, has y-intercept equal to _________.
Held on 25 Jul 2021 · Verified 6 Jul 2026.
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