.∣A∣=ad−bc=15
where a,b,c,d∈±3,±2,±1,0
Case I: ad=9&bc=-6
For ad possible pairs are (3,3),(−3,−3).
For bc possible pairs are (3,−2),(−3,2),(−2,3),(2,−3)
So, total number of matrices in case I=2×4=8
Case II: ad=6&bc=-9
Similarly, total number of matrices in case II =2×4=8
Hence, total number of matrices are 16.