A=(x,y)∈Z×Z;(x−2)2+y2≤4
B=(x,y)≤Z×Z;x2+y2≤4
C=(x,y)∈Z×Z;(x−2)2+(y−2)2≤4

Here, we can see from the above diagram A∩B=(0,0),(1,0),(2,0),(1,1),(1,−1)⇒n(A∩B)=5
Similarly n(A∩C)=5
Relation from A∩B to A∩C=25×5=2p
⇒p=25
JEE Main 2021 — Mathematics Algebra
Let Z be the set of all integers,
A=(x,y)∈Z×Z:(x−2)2+y2≤4
B=(x,y)∈Z×Z:x2+y2≤4 and
C=(x,y)∈Z×Z:(x−2)2+(y−2)2≤4
If the total number of relations from A∩B to A∩C is 2p, then the value of p is:
Held on 27 Aug 2021 · Verified 6 Jul 2026.
25
9
16
49
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