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Let a_1,a_2,a_3,… be an A.P. If a_1+a_2+… +a_10 a_1+a_2+… +a_ = 100 ^2,p≠ 10, then a_11 a_10 is equal to :

JEE Main 2021 — Mathematics Algebra

2021mcqeasy

Let a1,a2,a3,…{a}_{1},{a}_{2},{a}_{3},\ldotsa1​,a2​,a3​,… be an A.P. If a1+a2+…+a10a1+a2+…+ap=100p2,p≠10,\frac{{a}_{1}+{a}_{2}+\ldots +{a}_{10}}{{a}_{1}+{a}_{2}+\ldots +{a}_{p}}=\frac{100}{{p}^{2}},p\neq 10,a1​+a2​+…+ap​a1​+a2​+…+a10​​=p2100​,p=10, then a11a10\frac{{a}_{11}}{{a}_{10}}a10​a11​​ is equal to :

Official previous-year question

Held on 31 Aug 2021 · Verified 6 Jul 2026.

Options

  1. A

    1921\frac{19}{21}2119​

  2. B

    100121\frac{100}{121}121100​

  3. C

    2119\frac{21}{19}1921​

  4. D

    121100\frac{121}{100}100121​

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