Let A=1,2,3,…,10 and f:A→A be defined as
f(k)={\begin{matrix}k+1 & \mathrm{if}k\mathrm{is}odd \\ k & \mathrm{if}k\mathrm{is}even\end{matrix}
Then the number of possible functions g:A→A such that gof=f is:
Held on 26 Feb 2021 · Verified 6 Jul 2026.
C510
55
5!
105
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