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If the greatest value of the term independent of x in the expansion of (x sinα +a cosα x)^10 is 10! (5!)^2, then the value of a is equal to:

JEE Main 2021 — Mathematics Algebra

2021mcqeasy

If the greatest value of the term independent of xxx in the expansion of (xsinα+acosαx)10{(x\mathrm{sin}\alpha +a\frac{\mathrm{cos}\alpha }{x})}^{10}(xsinα+axcosα​)10 is 10!(5!)2,\frac{10!}{{(5!)}^{2}},(5!)210!​, then the value of aaa is equal to:

Official previous-year question

Held on 25 Jul 2021 · Verified 6 Jul 2026.

Options

  1. A

    −1-1−1

  2. B

    111

  3. C

    −2-2−2

  4. D

    222

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