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If a+α =1,b+β =2 and af(x)+α f( 1 x)=bx+ β x,x≠ 0, then the value of the expression f(x)+f( 1 x) x+ 1 x is .

JEE Main 2021 — Mathematics Algebra

2021integerhard

If a+α=1,b+β=2a+\alpha =1,b+\beta =2a+α=1,b+β=2 and af(x)+αf(1x)=bx+βx,x≠0,af(x)+\alpha f(\frac{1}{x})=bx+\frac{\beta }{x},x\neq 0,af(x)+αf(x1​)=bx+xβ​,x=0, then the value of the expression f(x)+f(1x)x+1x\frac{f(x)+f(\frac{1}{x})}{x+\frac{1}{x}}x+x1​f(x)+f(x1​)​ is ___________.

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Held on 24 Feb 2021 · Verified 6 Jul 2026.

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