We have, Prn=Pr+1n
⇒(n−r)!n!=(n−r−1)!n!
⇒(n−r)=1…(1)
and Crn=Cr−1n
⇒r!(n−r)!n!=(r−1)!(n−r+1)!n!
⇒r(n−r)!1=(n−r+1)(n−r)!1
⇒n−r+1=r
⇒n+1=2r…(2)
From equation (1)&(2), we get
2r−1−r=1
⇒r=2.
JEE Main 2021 — Mathematics Algebra
If Prn=Pr+1n and Crn=Cr−1n, then the value of r is equal to:
Held on 25 Jul 2021 · Verified 6 Jul 2026.
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